M11.1MechanicsStretch

Functions of Time

When acceleration is not constant, SUVAT no longer works. Instead, displacement, velocity and acceleration are written as functions of time, and calculus links them — the bridge between Pure and Mechanics.

20 min Variable Acceleration
Edexcel Mechanics Y1 — Variable Acceleration playlist (Zeeshan Zamurred)Curated by Kepler, not produced by us. Watch it before the notes below.
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What you'll be able to do

  • Express s, v and a as functions of time
  • Evaluate these at a given time
  • Understand why SUVAT fails here
  • Find values like the initial velocity
1

Why not SUVAT?

SUVAT equations assume constant\textbf{constant} acceleration. When acceleration varies with time, you instead have expressions like s=t3−2ts = t^3 - 2t, and you use calculus to move between displacement, velocity and acceleration.

2

Evaluating at a time

Given a function of time, substitute the value of tt to find the quantity at that instant. For example, the initial value is found at t=0t = 0.

Example 1A particle has v=3t2−4v = 3t^2 - 4 (m/s). Find the velocity at t=2t = 2.
1Substitute t=2t = 2: 3(4)−43(4) - 4.
Answer88 m/s

Tip — The “initial” value of any quantity is just its value at t = 0.

3

Setting up problems

Often you are given one function and asked for things like “when is the particle at rest?” (set v=0v = 0) or “the initial acceleration” (the acceleration function at t=0t = 0). Translating words into a time-substitution or equation is the key skill.

Example 1For v=3t2−4v = 3t^2 - 4, when is the particle instantaneously at rest? (t > 0)
1Set v=0v = 0: 3t2=43t^2 = 4, so t2=43t^2 = \tfrac{4}{3}.
Answert=23≈1.15t = \tfrac{2}{\sqrt{3}} \approx 1.15 s

Formula recap

s=f(t), v=g(t), a=h(t)s = f(t), \ v = g(t), \ a = h(t)
Quantities as functions of time.
initial value=value at t=0\text{initial value} = \text{value at } t = 0
Initial conditions.
v=0⇒at restv = 0 \Rightarrow \text{at rest}
Instantaneously at rest.

Common mistakes to avoid

Using SUVAT when acceleration varies.
SUVAT needs constant acceleration; use calculus instead.
Confusing “at rest” (v = 0) with “at the origin” (s = 0).
At rest means velocity 0; at the origin means displacement 0.

Key takeaways

  • Variable acceleration ⟶ s, v, a are functions of time (no SUVAT).
  • Substitute t to evaluate; t = 0 gives initial values.
  • Set v = 0 for “at rest”; s = 0 for “at the origin”.

Test yourself

Answer a few questions, then review anything you missed.

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Keep practising

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