4.3PureStretch

Using Partial Fractions

A rational function with a factorised denominator can be split into partial fractions, each of which is easy to expand binomially. Combining the expansions gives the series for the whole expression.

30 min Binomial Expansion
Edexcel A level Maths: (Part 1) 4.3 Using Partial Fractions in Binomial ExpansionCurated by Kepler, not produced by us. Watch it before the notes below.
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What you'll be able to do

  • Split a rational expression into partial fractions
  • Rewrite each fraction with a negative power
  • Expand each part binomially
  • Combine and state the overall range of validity
1

The strategy

First decompose into partial fractions. Then write each denominator as a bracket raised to a negative power, e.g. A1−x=A(1−x)−1\tfrac{A}{1-x} = A(1-x)^{-1}, and expand each binomially. Add the series term by term.

f(x)(1+ax)(1+bx)=A1+ax+B1+bx\frac{f(x)}{(1+ax)(1+bx)} = \frac{A}{1+ax} + \frac{B}{1+bx}
Decompose, then expand each part.
2

Overall validity

Each expansion has its own range of validity. The combined series is valid only where all\textbf{all} of them hold — take the most restrictive (smallest) range.

Tip — Overall validity = the strictest (smallest) of the individual ranges.

3

Worked example

Expand 3x(1+x)(1−2x)\dfrac{3x}{(1+x)(1-2x)}.

Example 1Express in partial fractions then find the first two terms.
1Partial fractions: −11+x+11−2x\tfrac{-1}{1+x} + \tfrac{1}{1-2x}.
2−(1+x)−1=−(1−x+⋯ )-(1+x)^{-1} = -(1 - x + \cdots); (1−2x)−1=1+2x+⋯(1-2x)^{-1} = 1 + 2x + \cdots.
3Sum: (−1+1)+(1+2)x+⋯=3x+⋯(-1+1) + (1+2)x + \cdots = 3x + \cdots
Answer
3x+⋯3x + \cdots, valid for ∣x∣<12|x| < \tfrac12.

Formula recap

A1+ax=A(1+ax)−1\frac{A}{1+ax} = A(1+ax)^{-1}
Negative-power form for expansion.
validity=min⁡ of each part\text{validity} = \min\text{ of each part}
Strictest range wins.

Common mistakes to avoid

Taking the widest range of validity.
The combined series needs every part to converge — use the smallest range.
Expanding before decomposing.
Split into partial fractions first; each part is then a simple binomial.

Key takeaways

  • Decompose into partial fractions first.
  • Write each as a negative power and expand binomially.
  • Combine series; validity is the strictest individual range.

Test yourself

Answer a few questions, then review anything you missed.

Prefer paper? Open the written self-check

Answer each question before opening its answer. This self-check does not record a quiz score.

  1. Before binomially expanding a rational function, you should:

    • split into partial fractions
    • differentiate it
    • square it
    • integrate it
    Show answer and explanation

    Answer: split into partial fractions

    Each part is then a simple binomial.

  2. A1−x\tfrac{A}{1-x} is rewritten for expansion as:

    • A(1−x)−1A(1-x)^{-1}
    • A(1−x)A(1-x)
    • A(1+x)−1A(1+x)^{-1}
    • A(1−x)1A(1-x)^{1}
    Show answer and explanation

    Answer: A(1−x)−1A(1-x)^{-1}

    Negative power.

  3. If one part is valid for ∣x∣<1|x|<1 and another for ∣x∣<12|x|<\tfrac12, the combined series is valid for:

    • ∣x∣<12|x| < \tfrac12
    • ∣x∣<1|x| < 1
    • ∣x∣<32|x| < \tfrac32
    • all xx
    Show answer and explanation

    Answer: ∣x∣<12|x| < \tfrac12

    Strictest range.

  4. The expansion of (1−2x)−1(1-2x)^{-1} begins:

    • 1+2x+⋯1 + 2x + \cdots
    • 1−2x+⋯1 - 2x + \cdots
    • 1+x+⋯1 + x + \cdots
    • 1−x+⋯1 - x + \cdots
    Show answer and explanation

    Answer: 1+2x+⋯1 + 2x + \cdots

    nx with n=−1, X=−2x gives +2x.

  5. Partial fractions are useful here because each piece:

    • is a simple binomial to expand
    • cancels to zero
    • has no x
    • is already a series
    Show answer and explanation

    Answer: is a simple binomial to expand

    Single bracket to a negative power.

Next step

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Related lessons

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