2.2StatisticsStretch

Conditional Probability

Conditional probability is the probability of one event given that another has already happened. It is written P(A | B) and computed by restricting attention to the outcomes where B occurs.

24 min Conditional Probability
Edexcel A level Maths: 2.2 Conditional ProbabilityCurated by Kepler, not produced by us. Watch it before the notes below.
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What you'll be able to do

  • Define P(A | B)
  • Use the conditional probability formula
  • Recognise independence
  • Apply to real contexts
1

The formula

The probability of AA given BB is P(A∣B)=P(A∩B)P(B)P(A \mid B) = \dfrac{P(A \cap B)}{P(B)} — the fraction of BB’s outcomes that are also in AA.

P(A∣B)=P(A∩B)P(B)P(A \mid B) = \frac{P(A \cap B)}{P(B)}
Conditional probability.
Example 1Given P(A∩B)=0.2P(A \cap B) = 0.2 and P(B)=0.5P(B) = 0.5, find P(A∣B)P(A \mid B).
10.20.5\dfrac{0.2}{0.5}.
2=0.4= 0.4.
Answer
0.40.4

Tip — Conditioning on B means dividing by P(B) — you’re working within B’s world.

2

Independence

If AA and BB are independent then P(A∣B)=P(A)P(A \mid B) = P(A) — knowing BB tells you nothing about AA. Equivalently P(A∩B)=P(A)P(B)P(A \cap B) = P(A)P(B).

Formula recap

P(A∣B)=P(A∩B)P(B)P(A \mid B) = \frac{P(A \cap B)}{P(B)}
Conditional probability.
P(A∩B)=P(A)P(B) (independent)P(A \cap B) = P(A)P(B) \ (\text{independent})
Independence.

Common mistakes to avoid

Dividing by P(A) instead of P(B) for P(A | B).
Divide by the probability of the given event, P(B).
Assuming events are always independent.
Check P(A∩B) = P(A)P(B) before assuming independence.

Key takeaways

  • P(A | B) = P(A∩B)/P(B).
  • Conditioning on B means dividing by P(B).
  • Independent: P(A | B) = P(A), so P(A∩B) = P(A)P(B).

Test yourself

Answer a few questions, then review anything you missed.

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Answer each question before opening its answer. This self-check does not record a quiz score.

  1. P(A∣B)P(A \mid B) equals:

    • P(A∩B)P(B)\frac{P(A \cap B)}{P(B)}
    • P(A∩B)P(A)\frac{P(A \cap B)}{P(A)}
    • P(A)P(B)P(A)P(B)
    • P(A)+P(B)P(A) + P(B)
    Show answer and explanation

    Answer: P(A∩B)P(B)\frac{P(A \cap B)}{P(B)}

    Divide by the given event.

  2. With P(A∩B)=0.2P(A \cap B)=0.2, P(B)=0.5P(B)=0.5, P(A∣B)=P(A\mid B)=

    • 0.40.4
    • 0.10.1
    • 0.70.7
    • 0.250.25
    Show answer and explanation

    Answer: 0.40.4

    0.2/0.5.

  3. If A and B are independent, P(A∣B)P(A \mid B) equals:

    • P(A)P(A)
    • P(B)P(B)
    • 00
    • 11
    Show answer and explanation

    Answer: P(A)P(A)

    B gives no info.

  4. Independence means P(A∩B)=P(A \cap B) =

    • P(A)P(B)P(A)P(B)
    • P(A)+P(B)P(A)+P(B)
    • P(A)−P(B)P(A)-P(B)
    • 00
    Show answer and explanation

    Answer: P(A)P(B)P(A)P(B)

    Multiply.

  5. P(A | B) restricts attention to outcomes where:

    • B occurs
    • A occurs
    • neither occurs
    • both fail
    Show answer and explanation

    Answer: B occurs

    Given B.

Next step

Check your understanding

Work through questions on Conditional Probability. Use the feedback to decide what needs another look.

1 past-paper question · 2 marks

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