9.3PureStretch

The Chain Rule

The chain rule differentiates a composite function — a function of a function. It is the most-used differentiation rule in Year 2, underpinning the product, quotient, parametric and implicit methods.

26 min Differentiation
Edexcel A level Maths: 9.3 The Chain RuleCurated by Kepler, not produced by us. Watch it before the notes below.
Open on YouTube

What you'll be able to do

  • State and apply the chain rule
  • Differentiate composite functions
  • Use the dy/dx = dy/du · du/dx form
  • Differentiate powers of functions quickly
1

The rule

If yy is a function of uu and uu is a function of xx, then dydx=dydu×dudx\dfrac{dy}{dx} = \dfrac{dy}{du} \times \dfrac{du}{dx}. Differentiate the outer function, then multiply by the derivative of the inside.

dydx=dydu⋅dudx\frac{dy}{dx} = \frac{dy}{du} \cdot \frac{du}{dx}
Chain rule.
Example 1Differentiate y=(2x+1)5y = (2x + 1)^5.
1Let u=2x+1u = 2x+1, y=u5y = u^5.
2dydu=5u4\tfrac{dy}{du} = 5u^4, dudx=2\tfrac{du}{dx} = 2.
3dydx=5(2x+1)4⋅2=10(2x+1)4\tfrac{dy}{dx} = 5(2x+1)^4 \cdot 2 = 10(2x+1)^4.
Answer
10(2x+1)410(2x+1)^4

Tip — “Differentiate the outside, keep the inside, times the derivative of the inside.”

2

A useful corollary

A related result: dydx=1 dx/dy \dfrac{dy}{dx} = \dfrac{1}{\,dx/dy\,}, handy when xx is easier to express in terms of yy.

Formula recap

dydx=dydu⋅dudx\frac{dy}{dx} = \frac{dy}{du} \cdot \frac{du}{dx}
Chain rule.
dydx=1dx/dy\frac{dy}{dx} = \frac{1}{dx/dy}
Reciprocal form.

Common mistakes to avoid

Forgetting to multiply by the derivative of the inside.
Always times du/dx.
Differentiating the inside function as well as the outside in one step incorrectly.
Outer derivative × inner derivative, kept separate.

Key takeaways

  • dy/dx = dy/du · du/dx.
  • Differentiate outside, keep inside, × derivative of inside.
  • dy/dx = 1/(dx/dy) when convenient.

Test yourself

Answer a few questions, then review anything you missed.

Prefer paper? Open the written self-check

Answer each question before opening its answer. This self-check does not record a quiz score.

  1. The chain rule states dy/dx =

    • dydu⋅dudx\frac{dy}{du}\cdot\frac{du}{dx}
    • dydu+dudx\frac{dy}{du}+\frac{du}{dx}
    • dudy⋅dxdu\frac{du}{dy}\cdot\frac{dx}{du}
    • dydx\frac{dy}{dx}
    Show answer and explanation

    Answer: dydu⋅dudx\frac{dy}{du}\cdot\frac{du}{dx}

    Product of derivatives.

  2. ddx(2x+1)5\frac{d}{dx}(2x+1)^5 equals:

    • 10(2x+1)410(2x+1)^4
    • 5(2x+1)45(2x+1)^4
    • (2x+1)4(2x+1)^4
    • 10(2x+1)510(2x+1)^5
    Show answer and explanation

    Answer: 10(2x+1)410(2x+1)^4

    5u⁴·2.

  3. ddx ex2\frac{d}{dx}\,e^{x^2} equals:

    • 2xex22x e^{x^2}
    • ex2e^{x^2}
    • x2ex2x^2 e^{x^2}
    • 2xe2x2x e^{2x}
    Show answer and explanation

    Answer: 2xex22x e^{x^2}

    e^u·u′ with u=x².

  4. The reciprocal form is dy/dx =

    • 1dx/dy\frac{1}{dx/dy}
    • dx/dydx/dy
    • dydx\frac{dy}{dx}
    • 11
    Show answer and explanation

    Answer: 1dx/dy\frac{1}{dx/dy}

    Useful when x(y) is simpler.

  5. ddxsin⁡(3x)\frac{d}{dx}\sin(3x) equals:

    • 3cos⁡(3x)3\cos(3x)
    • cos⁡(3x)\cos(3x)
    • −3cos⁡(3x)-3\cos(3x)
    • 3sin⁡(3x)3\sin(3x)
    Show answer and explanation

    Answer: 3cos⁡(3x)3\cos(3x)

    cos(3x)·3.

Next step

Keep practising

Start with the quiz above to check the key ideas. You can also choose another topic from the practice library.

Browse practice topics

Related lessons

All 10 lessons

Put the methods into practice: see how A-Level maths duels work. An account is required to play; the overview and sample are public.