3.2PureCore

Arithmetic Series

An arithmetic series is the sum of the terms of an arithmetic sequence. Two equivalent formulas give the sum of the first n terms instantly — no need to add them one by one.

25 min Sequences and Series
Edexcel A level Maths: 3.2 Arithmetic SeriesCurated by Kepler, not produced by us. Watch it before the notes below.
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What you'll be able to do

  • Use the sum formula Sₙ = n/2(2a + (n−1)d)
  • Use the alternative Sₙ = n/2(a + l)
  • Find n given a target sum
  • Apply the sum of natural numbers
1

The sum formulas

The sum of the first nn terms has two equivalent forms — use the first when you know aa and dd, the second when you know the first term aa and last term ll.

Sn=n2(2a+(n−1)d)S_n = \tfrac{n}{2}\big(2a + (n-1)d\big)
Using first term and common difference.
Sn=n2(a+l)S_n = \tfrac{n}{2}(a + l)
Using first and last terms.
Example 1Find the sum of the first 20 terms of 3, 7, 11, …
1a=3a = 3, d=4d = 4, n=20n = 20.
2S20=202(2(3)+19(4))=10(6+76)S_{20} = \tfrac{20}{2}(2(3) + 19(4)) = 10(6 + 76).
Answer
820820
2

Finding n

If a target sum is given, substitute into SnS_n to get a quadratic in n\textbf{quadratic in } n, then solve (discard non-positive or non-integer solutions).

Tip — Setting Sₙ equal to a value gives a quadratic in n — solve and keep the sensible (positive integer) root.

3

Sum of natural numbers

A special case: 1+2+⋯+n=n(n+1)21 + 2 + \cdots + n = \tfrac{n(n+1)}{2} (here a=1a = 1, d=1d = 1). This appears often in proofs and sigma-notation work.

1+2+⋯+n=n(n+1)21 + 2 + \cdots + n = \tfrac{n(n+1)}{2}
Sum of the first nn natural numbers.

Formula recap

Sn=n2(2a+(n−1)d)S_n = \tfrac{n}{2}(2a + (n-1)d)
Sum (a and d).
Sn=n2(a+l)S_n = \tfrac{n}{2}(a + l)
Sum (first and last).
∑1nr=n(n+1)2\sum_{1}^{n} r = \tfrac{n(n+1)}{2}
Sum of 1…n.

Common mistakes to avoid

Using the geometric sum formula for an arithmetic series.
Arithmetic series use n/2(2a + (n−1)d), not a(1−rⁿ)/(1−r).
Keeping a negative or fractional n.
n must be a positive integer — discard other roots.

Key takeaways

  • Sₙ = n/2(2a + (n−1)d) or n/2(a + l).
  • A target sum gives a quadratic in n.
  • 1 + 2 + … + n = n(n+1)/2.

Test yourself

Answer a few questions, then review anything you missed.

Prefer paper? Open the written self-check

Answer each question before opening its answer. This self-check does not record a quiz score.

  1. The sum of an arithmetic series is:

    • n2(2a+(n−1)d)\tfrac{n}{2}(2a + (n-1)d)
    • a+(n−1)da + (n-1)d
    • a(1−rn)1−r\tfrac{a(1-r^n)}{1-r}
    • arn−1ar^{n-1}
    Show answer and explanation

    Answer: n2(2a+(n−1)d)\tfrac{n}{2}(2a + (n-1)d)

    The arithmetic sum formula.

  2. The sum of the first 20 terms of 3, 7, 11, … is:

    • 820820
    • 800800
    • 420420
    • 16401640
    Show answer and explanation

    Answer: 820820

    10(6 + 76) = 820.

  3. Sn=n2(a+l)S_n = \tfrac{n}{2}(a + l) uses the first term and the:

    • Last term
    • Common difference
    • Common ratio
    • Number of terms only
    Show answer and explanation

    Answer: Last term

    l is the last term.

  4. 1+2+⋯+1001 + 2 + \cdots + 100 equals:

    • 50505050
    • 1000010000
    • 50005000
    • 255255
    Show answer and explanation

    Answer: 50505050

    100(101)/2.

  5. Setting Sₙ equal to a given value produces:

    • A quadratic in n
    • A linear equation
    • A geometric series
    • No equation
    Show answer and explanation

    Answer: A quadratic in n

    n appears squared.

  6. When solving for n, you keep values that are:

    • Positive integers
    • Any real number
    • Negative
    • Fractions
    Show answer and explanation

    Answer: Positive integers

    n counts terms.

Next step

Keep practising

Start with the quiz above to check the key ideas. You can also choose another topic from the practice library.

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