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A balanced chemical equation has the same number of each kind of atom on both sides. Change coefficients, not the subscripts inside correct formulae. Relative formula mass adds the relative atomic masses of all atoms in a formula unit. In a closed reaction system mass is conserved; an apparent mass change can occur if a gas enters or leaves an open container. The missing or gained gas is part of the mass balance.
Video by Cognito. The video’s own board label is retained; follow the specification reference and scope notes on this lesson for assessed content.
Viewing focus: Balance equations and calculate formula mass
After watching, attempt these questions before opening the answers. You can also use the written lesson below.
After watching 1: What is the formula mass of CO2 using C = 12 and O = 16?
44. 12 + 2 × 16 = 44.
After watching 2: Can balanced-equation mole ratios be applied directly as mass ratios?
No. Convert each mass to moles first.
What you'll be able to do
A balanced chemical equation has the same number of each kind of atom on both sides. Change coefficients, not the subscripts inside correct formulae. Relative formula mass adds the relative atomic masses of all atoms in a formula unit. In a closed reaction system mass is conserved; an apparent mass change can occur if a gas enters or leaves an open container. The missing or gained gas is part of the mass balance.
One mole contains the Avogadro constant of the specified particles. Calculate amount with n = m/M, then apply the equation’s coefficient ratio before converting to the requested mass. When two reactants are supplied, compare their available amounts with the required ratio. The limiting reactant determines theoretical product. For solutions, concentration in g dm⁻³ equals mass divided by volume; molar concentration uses amount divided by volume. State which concentration unit is intended.
Percentage yield is actual product divided by theoretical product times 100. Atom economy measures the fraction of reactant atoms ending in the desired product, calculated from the balanced equation masses. Loss during transfer, incomplete reaction and competing reactions can lower yield. Wet or impure product can falsely increase measured yield. A gas-volume calculation needs the molar volume supplied for the stated conditions; do not assume a value applies at every temperature and pressure.
Attempt these problems on paper before opening the worked reasoning. Explain your steps as well as giving a final answer.
Common mistakes to avoid
Key takeaways
Question 1: 4.0 g product is isolated from a theoretical 5.0 g. Calculate percentage yield.
80%.
Check the assessed scope and practical or mathematical requirements.
An external explanation or interactive activity to use alongside the lesson. It may include extension material.
Close the notes and answer from memory. Revisit any explanation you cannot yet reconstruct.
Test yourself
Answer a few questions, then review anything you missed.
Start with the quiz above to check the key ideas. You can also choose another topic from the practice library.