- Describe the locus of points that are the same distance from two straight lines that meet at a point.[1]
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With only a ruler and a pair of compasses you can bisect an angle, draw a perpendicular exactly through the middle of a line, and mark out every point a given distance from a landmark. These solve problems: where can a goat tethered to a post graze? Which part of a park is closer to the café than the gate?
The big picture
Constructions work because compasses draw points at exactly equal distances. Every standard construction uses that fact — two arcs of the same radius crossing at points equidistant from two things — which is why the arcs must be left visible as evidence.
A locus is a set of points obeying a rule. Four loci cover almost every GCSE question: a fixed distance from a point (circle), a fixed distance from a line (parallel lines with semicircular ends), equidistant from two points (perpendicular bisector), and equidistant from two lines (angle bisector).
What you'll learn
To bisect line segment at right angles: set the compasses to more than half the length of . Draw arcs from above and below the line, then, with the same radius, arcs from crossing them.
Join the two crossing points with a straight line. It passes through the midpoint of at .
Every point on this line is the same distance from as from .
Tip — Keep the compass width fixed for both sets of arcs, and never rub out construction arcs — they are the evidence for the marks.
To bisect an angle at vertex : draw an arc centred at crossing both arms. From each crossing point, draw arcs of equal radius that meet inside the angle. Join to the meeting point.
Every point on the angle bisector is equidistant from the two arms.
To draw a perpendicular from a point to a line: draw an arc from cutting the line twice, then construct the perpendicular bisector of those two points; it passes through .
The shortest distance from a point to a line is along the perpendicular. That is why "distance from a line" in loci problems always means the perpendicular distance.
Given three sides (SSS): draw one side accurately, then use compasses set to each of the other lengths from its ends; the arcs cross at the third vertex.
Given two sides and the included angle (SAS), or two angles and a side (ASA), use a protractor for the angles and a ruler for the sides.
Label vertices and leave all arcs visible.
Can a triangle be constructed with sides of 3 cm, 4 cm and 8 cm? Type yes or no.
Points a fixed distance from a point form a . Points a fixed distance from a line segment form a "running track" shape: two parallel lines joined by semicircles.
Points equidistant from two points lie on the . Points equidistant from two intersecting lines lie on the .
"Closer to than " means one side of the perpendicular bisector; "less than 3 m from " means inside a circle. Combine conditions by finding where all regions overlap, and shade that region.
A straight fence is 10 m long. Find the area of the region within 3 m of the fence (on both sides, including the rounded ends), to 1 decimal place.
Tip — Convert real distances with the scale before drawing. With 1 cm to 2 m, a 5 m radius becomes 2.5 cm.
Think like an examiner
Loci
Watch out for these
Stretch yourself
Two phone masts and are 8 km apart. A signal is received anywhere within 5 km of either mast. Explain which points on the perpendicular bisector of receive a signal, and find the length of that section.
Hint — Points on the perpendicular bisector are equidistant from and . Use Pythagoras with half of .
Questions students ask
Key takeaways
Exam-style questions
3 original questions · 7 marks, written to match the style and mark allocation of the real papers. Work on paper, then open the mark scheme and tick the marks you earned — method marks count even if the final answer slips.
A goat is tied to a corner post of a large rectangular field by a rope 7 m long.
Test yourself
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Real past-paper questions on Constructions & Loci, marked mark-by-mark. How you do feeds straight into your weak-topic list, so your revision keeps targeting what actually needs work.