In a group of 60 people, 34 have been to America, 20 have been to Brazil and 8 have been to both.
- A person who has been to America is chosen at random. Work out the probability they have also been to Brazil.[2]
The probability that a randomly chosen student plays tennis is one thing. The probability that a student plays tennis they play football is another — you already know something about them, so you only look at the footballers. That is , and it is the most challenging probability idea at GCSE.
The big picture
"Given that" shrinks the sample space. Instead of dividing by everyone, divide by the group you are told about. In a Venn diagram or two-way table, that means using the total of the given set as the denominator.
Written as P(), the probability of given equals . Edexcel sets conditional probability questions using Venn diagrams, two-way tables and tree diagrams, and they are usually worth 2–4 marks each.
What you'll learn
P() is read "the probability of given ". You already know has happened, so only outcomes in are possible.
So P() .
Using probabilities: P() .
In a class of 40, 22 dance, 15 sing and 6 do both. A singer is chosen at random. Find the probability that they also dance.
Tip — Underline the "given" condition in the question. Its total is your denominator.
A two-way table shows counts for two categories. For a conditional probability, find the row or column for the given condition and use its total.
Of 30 adults, 18 own a dog. Of 20 children, 8 own a dog. A dog owner is chosen at random. Find the probability it is a child.
P(Year 11 | museum) is not the same as P(museum | Year 11) . Swapping the condition changes the denominator — confusing the two is the classic error.
On a tree diagram, second-stage branches often show conditional probabilities: P(second event | first outcome).
Multiplying along a path uses P( and ) P() × P().
A team wins its first game with probability 0.4. If it wins, it wins the second with probability 0.7; if it loses, it wins the second with probability 0.2. Find the probability it wins the second game.
Sometimes you know the second event happened and want the probability of the first: for example, given the bus was late, what is the probability it rained?
Use P(rain | late) , taking both from the tree.
Using the same team, find the probability it won the first game, given that it won the second.
Tip — The numerator is one path; the denominator is the sum of all paths that satisfy the given condition.
Think like an examiner
Conditional probability
Watch out for these
Stretch yourself
A test for a condition that affects 1 in 50 people gives a positive result for 95% of people with the condition and for 4% of people without it. A person tests positive. Find the probability that they have the condition, to 3 significant figures.
Hint — Draw a tree: condition or not, then positive or negative. Divide the "condition and positive" path by all positive paths.
Questions students ask
Key takeaways
Exam-style questions
3 original questions · 8 marks, written to match the style and mark allocation of the real papers. Work on paper, then open the mark scheme and tick the marks you earned — method marks count even if the final answer slips.
In a group of 60 people, 34 have been to America, 20 have been to Brazil and 8 have been to both.
Ana travels by car with probability 0.6, otherwise by bus. By car she is late with probability 0.1; by bus, with probability 0.25.
A bag contains 6 red and 4 blue counters. Two counters are taken at random without replacement.
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