1MA1 · S3StatisticsHigherGrades 7–8

Histograms

Q: When do I need frequency density?

Whenever classes have unequal widths. With equal widths, bar heights can be frequencies, but density is still correct.

Q: How is a histogram different from a bar chart?

Histograms show continuous data with touching bars whose area represents frequency; bar charts show categories with gaps.

Q: What does a tall, thin bar mean?

Many values packed into a narrow range — high density.

A histogram looks like a bar chart for continuous data, but with one crucial difference: when the classes have different widths, the height of each bar is not the frequency. It is the $frequency density$ , chosen so that the $area$ of each bar represents the frequency. Getting that idea right is the whole of this topic.

45 min Statistics

The big picture

If a class twice as wide were drawn at its frequency, it would look twice as important simply because it is wide. Dividing frequency by class width fixes this: frequency density is frequency per unit, so the bar’s area — width × density — equals the frequency.

Edexcel histogram questions work in both directions: complete a table and draw the histogram, or read frequencies from a drawn histogram, often for part of a class, such as "estimate the number of values between 12 and 25".

What you'll learn

Calculate frequency density for classes of unequal width
Draw histograms with frequency density on the vertical axis
Find frequencies from a histogram using area
Estimate frequencies within part of a class and estimate the median

Frequency density

Frequency density $= \frac{frequency}{class width}$ .

Frequency $=$ frequency density × class width — the area of the bar.

Class width is the difference between the class boundaries: $15 \leq t < 20$ has width 5.

frequency density = \frac{frequency}{class width}

Bar height.

frequency = density \times width

Bar area.

12 \div 10 = 1.2

20 \div 5 = 4

18 \div 5 = 3.6

30 \div 20 = 1.5

AnswerFrequency densities 1.2, 4, 3.6, 1.5

Your turnSame method, new numbers — try it before moving on.

A class of width 15 has frequency 45. What is its frequency density?

Your answer

Drawing histograms

Use a continuous horizontal scale with class boundaries; bars touch, with no gaps.

The vertical axis is labelled "frequency density" with an even scale.

Each bar spans its class exactly, with height equal to its frequency density.

Tip — Label the vertical axis "frequency density", not "frequency". Using frequency heights with unequal widths loses most of the marks.

Reading histograms

To find the frequency of a class, multiply its height (frequency density) by its width.

If the vertical scale is not labelled with numbers, use a class whose frequency is known to work out what one unit of area represents.

112 to 15 is in the class with density 4:

3 \times 4 = 12

215 to 20 is a whole class: 18.

320 to 25 is in the class with density 1.5:

5 \times 1.5 = 7.5

4Total

= 12 + 18 + 7.5

AnswerAbout 37.5, so roughly 37 or 38 values

Your turnSame method, new numbers — try it before moving on.

The bar for $30 \leq t < 50$ has frequency density 0.8. What is the frequency?

Your answer

Why this works

Taking part of a class assumes values are spread evenly across it — the same assumption as reading from a cumulative frequency curve. That is why the answer is an estimate.

Estimating the median

Find the total frequency and the median position $\frac{n}{2}$ .

Add class frequencies until you reach the class containing the median, then work out how far into that class you need to go.

1Median position: 40.

2Cumulative: 12 by 10, 32 by 15. Need 8 more from the class

15 \leq t < 20

, which has density 3.6.

3Width needed:

8 \div 3.6 = 2.22

, so median

\approx 15 + 2.22

AnswerMedian

\approx 17.2

Your turnSame method, new numbers — try it before moving on.

The class $10 \leq t < 20$ has frequency 30. Estimate how many values lie between 10 and 18.

Your answer

Think like an examiner

Label the vertical axis "frequency density".
Show width × density calculations when reading frequencies.
For part of a class, show the fraction of the width used.

Histograms

f.d. = \frac{f}{width}

Frequency density.

f = f.d. \times width

Frequency from a bar.

Watch out for these

Drawing bar heights as frequencies with unequal widths.

Heights must be frequency densities.

Using class midpoints as class widths.

Width is upper boundary minus lower boundary.

Reading the frequency straight off the vertical axis.

Multiply the height by the width.

Leaving gaps between bars.

Histogram bars touch because the data are continuous.

Stretch yourself

On a histogram with no numbers on the vertical axis, the bar for $10 \leq x < 20$ is 6 cm tall and represents 42 people. The bar for $20 \leq x < 25$ is 8 cm tall. How many people does it represent?

Hint — Work out how many people 1 cm² of bar represents, using horizontal distance in class units.

Questions students ask

When do I need frequency density?

Whenever classes have unequal widths. With equal widths, bar heights can be frequencies, but density is still correct.

How is a histogram different from a bar chart?

Histograms show continuous data with touching bars whose area represents frequency; bar charts show categories with gaps.

What does a tall, thin bar mean?

Many values packed into a narrow range — high density.

Key takeaways

Frequency density $=$ frequency ÷ class width.
In a histogram, bar area represents frequency.
Bars touch and the vertical axis is frequency density.
Read frequencies with width × density, including parts of classes.
Estimate the median by finding how far into the median class the middle value lies.

Exam-style questions

Practise it the way it is examined

2 original questions · 7 marks, written to match the style and mark allocation of the real papers. Work on paper, then open the mark scheme and tick the marks you earned — method marks count even if the final answer slips.

Question 1Grade 74 marks

Heights: $0 < h \leq 20$ : 10; $20 < h \leq 30$ : 24; $30 < h \leq 35$ : 15; $35 < h \leq 50$ : 18.

(a)Work out the frequency densities.[2]
(b)Estimate the number of heights greater than 32.[2]

Question 2Grade 83 marks

Use the same data (total 67).

Estimate the median height.[3]

Unlimited practice

Skill drill

A new question every time, marked instantly, with a full worked solution. Aim for a streak of five, then move up a level.

0 / 0 first-time correct Streak 0Best at this level: 0

Generating a question…

Test yourself

Ready to practise Histograms? Pick a mode and earn XP & Dobloons.

Next step

Practise this topic

Real past-paper questions on Histograms, marked mark-by-mark. How you do feeds straight into your weak-topic list, so your revision keeps targeting what actually needs work.

Practise this topic

Histograms

Frequency density

Drawing histograms

Reading histograms

Estimating the median

Practise it the way it is examined

Skill drill

Practise this topic

Related topics

Histograms

Frequency density

Drawing histograms

Reading histograms

Estimating the median

Practise it the way it is examined

Skill drill

Practise this topic

Related topics