140–143Nuclear and Particle PhysicsStretch

Quarks, Leptons and the Standard Model

By the 1960s accelerators had found hundreds of new particles. The standard model\textbf{standard model} brought order to them: everything is built from a small set of fundamental particles — six quarks\textbf{quarks} and six leptons\textbf{leptons}, each with an antiparticle — held together by exchange of force-carrying particles.

40 min Topic 8 · Nuclear and Particle Physics

What you'll be able to do

  • Classify particles as quarks, leptons, baryons and mesons
  • Determine the quark composition and charge of hadrons
  • Describe antiparticles and their properties
  • Apply conservation of charge, baryon number and lepton number to interactions
1

Fundamental particles

Quarks\textbf{Quarks} come in six flavours: up, down, strange, charm, top and bottom. Up, charm and top have charge +23e+\tfrac23 e; down, strange and bottom have −13e-\tfrac13 e. Quarks are never observed alone.

Leptons\textbf{Leptons} are the electron, muon and tau, each with charge −e-e, plus a neutral neutrino for each. Leptons are not made of quarks and do not feel the strong nuclear force.

Every particle has an antiparticle\textbf{antiparticle} with the same mass and the opposite charge, baryon number and lepton number. The antiparticle of the electron is the positron; an anti-up quark has charge −23e-\tfrac23 e.

u:+23ed:−13es:−13eu: +\tfrac23 e \qquad d: -\tfrac13 e \qquad s: -\tfrac13 e
Charges of the three lightest quarks.

Tip — Almost every exam question only needs uu, dd and ss and their antiquarks. Know those charges without hesitation.

2

Hadrons: baryons and mesons

Particles made of quarks are hadrons\textbf{hadrons}, and they feel the strong force. There are two families.

Baryons\textbf{Baryons} contain three quarks and have baryon number +1+1. The proton is uuduud, charge 23+23−13=+1\tfrac23 + \tfrac23 - \tfrac13 = +1; the neutron is uddudd, charge 23−13−13=0\tfrac23 - \tfrac13 - \tfrac13 = 0. Antibaryons are three antiquarks with baryon number −1-1.

Mesons\textbf{Mesons} contain one quark and one antiquark, so they have baryon number 00. The positive pion is udˉu\bar{d}, charge 23+13=+1\tfrac23 + \tfrac13 = +1.

Each quark carries baryon number +13+\tfrac13 and each antiquark −13-\tfrac13, which is why three quarks give +1+1 and a quark–antiquark pair gives 00.

Example 1A particle has quark composition usˉu\bar{s}. Find its charge and baryon number, and classify it.
1Charge: +23+(+13)=+1+\tfrac23 + \left(+\tfrac13\right) = +1, since the anti-strange quark has charge +13+\tfrac13.
2Baryon number: 13−13=0\tfrac13 - \tfrac13 = 0.
AnswerCharge +e+e, baryon number 0: a meson (the positive kaon).
3

Conservation laws

In every particle interaction, these quantities are conserved: charge\textbf{charge}, baryon number\textbf{baryon number}, lepton number\textbf{lepton number}, and also energy and momentum.

Leptons have lepton number +1+1 and antileptons −1-1. Hadrons have lepton number 00.

To test whether an interaction is possible, tabulate each quantity for every particle on both sides. If any total differs, the interaction is forbidden.

Example 1Is p+p→p+n+π+p + p \rightarrow p + n + \pi^{+} possible?
1Charge: 1+1=21 + 1 = 2; right 1+0+1=21 + 0 + 1 = 2. ✓
2Baryon number: 1+1=21 + 1 = 2; right 1+1+0=21 + 1 + 0 = 2. ✓
3Lepton number: 0=00 = 0. ✓
AnswerAll conserved, so it is allowed (given enough kinetic energy).
Example 2Is n→p+e−n \rightarrow p + e^{-} possible?
1Charge: 0=1−10 = 1 - 1. ✓
2Baryon number: 1=1+01 = 1 + 0. ✓
3Lepton number: 00 on the left; 0+1=10 + 1 = 1 on the right. ✗
AnswerForbidden: lepton number is not conserved. An antineutrino must also be produced.

Tip — Set conservation checks out as a table with one row per quantity. It is quicker, and markers can award credit line by line.

4

Beta decay and the forces

In β−\beta^{-} decay, a neutron becomes a proton: n→p+e−+νˉen \rightarrow p + e^{-} + \bar{\nu}_{e}. At quark level, a down quark changes to an up quark\textbf{down quark changes to an up quark}, which only the weak interaction can do.

In β+\beta^{+} decay, a proton in a nucleus becomes a neutron: p→n+e++νep \rightarrow n + e^{+} + \nu_{e}, an up quark changing to a down.

The standard model includes three forces relevant here, each carried by exchange particles: the electromagnetic\textbf{electromagnetic} force (photon), the strong\textbf{strong} force binding quarks (gluons), and the weak\textbf{weak} force responsible for changing quark flavour (W and Z bosons).

The existence of the neutrino was originally inferred from beta decay: electrons emerged with a range of energies instead of one fixed value, so an unseen particle had to be carrying the rest.

d→u+e−+νˉed \rightarrow u + e^{-} + \bar{\nu}_{e}
Quark-level β−\beta^{-} decay.

Equation recap

p=uud, n=uddp = uud,\ n = udd
Nucleon quark content.
Bq=+13, Bqˉ=−13B_{q} = +\tfrac13,\ B_{\bar{q}} = -\tfrac13
Baryon numbers.
n→p+e−+νˉen \rightarrow p + e^{-} + \bar{\nu}_{e}
β−\beta^{-} decay.

Common mistakes to avoid

Giving an antiquark the same charge as its quark.
Antiquarks have opposite charge: dˉ\bar{d} is +13e+\tfrac13 e.
Classifying the electron as a hadron.
The electron is a fundamental lepton with no quarks.
Assigning mesons baryon number 11.
Quark plus antiquark gives 13−13=0\tfrac13 - \tfrac13 = 0.
Omitting the antineutrino in β−\beta^{-} decay.
Lepton number requires it: e−e^{-} is +1+1, νˉ\bar{\nu} is −1-1.

Key takeaways

  • Six quarks and six leptons, each with an antiparticle, are fundamental.
  • Baryons are three quarks (B=1B = 1); mesons are quark–antiquark (B=0B = 0).
  • Proton uuduud, neutron uddudd.
  • Charge, baryon number and lepton number are conserved in all interactions.
  • β−\beta^{-} decay is d→ud \rightarrow u via the weak interaction, with an antineutrino emitted.

Test yourself

Answer a few questions, then review anything you missed.

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