1MA1 · G16–G17Geometry & MeasuresFoundation & HigherGrades 1–5

Perimeter & Area

Perimeter is the distance around the edge of a shape; area is the amount of flat surface it covers. A handful of formulas — for rectangles, triangles, parallelograms and trapezia — combine to handle almost any shape, including the L-shapes, gardens and floor plans that fill exam papers.

40 min Mensuration

The big picture

Every area formula grows out of the rectangle. A parallelogram rearranges into a rectangle, so its area is base × perpendicular height. A triangle is half a parallelogram. A trapezium averages its two parallel sides. Understanding these links means you can reconstruct any formula you forget.

Edexcel mensuration questions are often multi-step problems in context — the cost of turf for a garden, how many tiles fit a floor — where area is only one stage, and unit conversions like cm² to m² catch many candidates.

What you'll learn

  • Calculate perimeters of shapes, including compound shapes
  • Find areas of rectangles, triangles, parallelograms and trapezia
  • Find areas of compound shapes by adding and subtracting
  • Solve problems involving area in context, including unit conversions
1

Area formulas

Rectangle: length × width. Parallelogram: base × perpendicular height. Triangle: 12\tfrac12 × base × perpendicular height. Trapezium: 12(a+b)h\tfrac12(a + b)h, where aa and bb are the parallel sides.

The height must be perpendicular\textbf{perpendicular} to the base — not a slanting side.

A=12bhA = \tfrac12 bh
Triangle.
A=12(a+b)hA = \tfrac12(a + b)h
Trapezium.
Example 1Find the area of a trapezium with parallel sides 5 cm and 11 cm, and height 6 cm.
1A=12(5+11)×6A = \tfrac12(5 + 11) \times 6.
2=8×6= 8 \times 6.
Answer48 cm²
Your turnSame method, new numbers — try it before moving on.

Find the area of a triangle with base 9 cm and perpendicular height 7 cm, in cm².

Show worked solution
Solution
  1. 112×9×7=31.5\frac{1}{2} \times 9 \times 7 = 31.5 cm².

Answer: 31.531.5 cm²

Why this works

Two copies of a trapezium, one flipped, fit together to make a parallelogram with base a+ba + b and height hh. Half of that is the trapezium formula.

2

Perimeter

Perimeter is the total length of all the edges. For compound shapes, find any missing side lengths first using the lengths you know.

Perimeter is a length, measured in cm or m — not cm².

Example 1An L-shaped room is a 10 m by 8 m rectangle with a 4 m by 3 m rectangle removed from one corner. Find its perimeter and area.
1Removing a corner rectangle does not change the perimeter: the missing edges are replaced by equal inside edges.
2Perimeter =2(10+8)=36= 2(10 + 8) = 36 m.
3Area =80−12=68= 80 - 12 = 68 m².
AnswerPerimeter 36 m, area 68 m²
Your turnSame method, new numbers — try it before moving on.

A square has perimeter 28 cm. Find its area, in cm².

Show worked solution
Solution
  1. 1Side =28÷4=7= 28 \div 4 = 7 cm.
  2. 2Area =49= 49 cm².

Answer: 4949 cm²

Tip — For a compound shape, mark every side length on the diagram before adding. Missing sides are found by adding or subtracting known sides.

3

Compound shapes

Split a compound shape into rectangles, triangles and trapezia, find each area, then add.

Alternatively, find the area of a larger simple shape and subtract the parts that are missing — often quicker.

Example 1A path 1 m wide runs around the outside of a 12 m by 8 m lawn. Find the area of the path.
1Outer rectangle: 14×10=14014 \times 10 = 140 m².
2Lawn: 12×8=9612 \times 8 = 96 m².
3Path =140−96= 140 - 96.
Answer44 m²
Your turnSame method, new numbers — try it before moving on.

A path 2 m wide runs around the outside of a 10 m by 6 m lawn. Find the area of the path, in m².

Show hint

The outer rectangle is 14 m by 10 m.

Show worked solution
Solution
  1. 1Outer rectangle: 14×10=14014 \times 10 = 140 m².
  2. 2Path =140−60=80= 140 - 60 = 80 m².

Answer: 8080 m²

4

Units and problems

Area units are squared: 11 m² =100×100=10 000= 100 \times 100 = 10\,000 cm², and 11 cm² =100= 100 mm².

In cost or quantity problems, find the area, convert to the unit being priced, then round up to whole packs where needed.

Example 1Turf costs £4.50 per m² and is sold in whole square metres. A rectangular lawn measures 7.4 m by 5.2 m. How much does the turf cost?
1Area =38.48= 38.48 m².
2Buy 39 m² (round up).
3Cost =39×4.50= 39 \times 4.50.
Answer£175.50

Tip — In context, decide whether to round up (you need enough turf) or down (how many whole items fit). Explain your choice.

Think like an examiner

  • Write the formula, substitute, then calculate.
  • Include units: cm² for area, cm for perimeter.
  • Show the split of compound shapes clearly.

Area

A=lwA = lw
Rectangle.
A=bhA = bh
Parallelogram.
A=12bhA = \tfrac12 bh
Triangle.
A=12(a+b)hA = \tfrac12(a + b)h
Trapezium.

Watch out for these

Using the slant side as the height of a parallelogram.
Use the perpendicular height.
Forgetting the 12\tfrac12 for a triangle.
Triangle area is half base × height.
Converting 3 m² to 300 cm².
3×10 000=30 0003 \times 10\,000 = 30\,000 cm².
Giving perimeter in cm².
Perimeter is a length, in cm.

Stretch yourself

A rectangle has area 48 cm² and perimeter 28 cm. Find its length and width.

Hint — Let the sides be ll and ww. Write two equations and form a quadratic.

Reveal solution
SolutionFrom the perimeter, 2(l+w)=282(l + w) = 28, so l+w=14l + w = 14 and w=14−lw = 14 - l. From the area, l(14−l)=48l(14 - l) = 48, so l2−14l+48=0l^{2} - 14l + 48 = 0, which factorises as (l−6)(l−8)=0(l - 6)(l - 8) = 0. The sides are 8 cm and 6 cm. Check: 8×6=488 \times 6 = 48 ✓ and 2(8+6)=282(8 + 6) = 28 ✓. ■\blacksquare

Questions students ask

What is the difference between area and perimeter?
Perimeter measures the boundary (a length); area measures the surface enclosed (a squared unit).
Do I need to learn the trapezium formula?
Yes — it is not given on the Edexcel formula sheet.
How do I convert cm² to m²?
Divide by 10 000, because 1 m² is 100 cm by 100 cm.

Key takeaways

  • Perimeter: total length of the edges.
  • Rectangle lwlw; parallelogram bhbh; triangle 12bh\tfrac12 bh; trapezium 12(a+b)h\tfrac12(a + b)h.
  • Heights must be perpendicular.
  • Compound shapes: split and add, or subtract from a larger shape.
  • Area units scale by the square of length conversions.

Exam-style questions

Practise it the way it is examined

3 original questions · 6 marks, written to match the style and mark allocation of the real papers. Work on paper, then open the mark scheme and tick the marks you earned — method marks count even if the final answer slips.

Question 1Grade 21 mark
  1. A parallelogram has base 12 cm and perpendicular height 7 cm. Work out its area.[1]
    Show mark scheme

    Answer: 8484 cm²

Answer on paper first, then mark it.
Question 2Grade 42 marks
  1. A trapezium has area 60 cm² and parallel sides of 8 cm and 12 cm. Work out its height.[2]
    Show mark scheme

    Answer: 66 cm

Answer on paper first, then mark it.
Question 3Grade 53 marks
  1. A room is 4.2 m by 3.5 m. Carpet costs £18.50 per m² and is sold in whole square metres. Work out the cost of carpeting the room.[3]
    Show mark scheme

    Answer: £277.50

Answer on paper first, then mark it.

Unlimited practice

Skill drill

A new question every time, marked instantly, with a full worked solution. Aim for a streak of five, then move up a level.

0 / 0 first-time correct Streak 0Best at this level: 0

Generating a question…

Test yourself

Answer a few questions, then review anything you missed.

Next step

Keep practising

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