1MA1 · G7–G8, G24Geometry & MeasuresFoundation & HigherGrades 2–7

Transformations

A transformation moves or resizes a shape according to a rule. There are four at GCSE — translation, reflection, rotation and enlargement — and each needs specific information to describe it completely. "Describe fully the single transformation" questions are worth two or three marks, and most lost marks are for missing a detail such as the centre of rotation.

50 min Transformations & Vectors

The big picture

Translations, reflections and rotations keep a shape exactly the same size and shape: the image is congruent to the original. Enlargements change size but keep the shape: the image is similar. That distinction links this lesson directly to congruence and similarity.

Each transformation has a checklist. Translation: a column vector. Reflection: the mirror line. Rotation: angle, direction and centre. Enlargement: scale factor and centre. If your description has all the items on the checklist, it earns full marks.

What you'll learn

  • Translate shapes using column vectors
  • Reflect shapes in lines such as x=ax = a, y=by = b and y=±xy = \pm x
  • Rotate shapes about a centre, and find centres of rotation
  • Enlarge shapes with positive, fractional and negative scale factors, and describe transformations fully
1

Translations

A translation slides every point the same distance in the same direction, described by a column vector (xy)\begin{pmatrix} x \\ y \end{pmatrix}: xx units right (negative for left) and yy units up (negative for down).

To describe a translation, pick one vertex and its image, and count across and up.

(3−2): 3 right, 2 down\begin{pmatrix} 3 \\ -2 \end{pmatrix}: \text{ 3 right, 2 down}
Column vector for a translation.
Your turnSame method, new numbers — try it before moving on.

Translate the point (3,−2)(3, -2) by (−54)\begin{pmatrix} -5 \\ 4 \end{pmatrix}.

Type coordinates like (2, -3).

Show worked solution
Solution
  1. 13−5=−23 - 5 = -2 and −2+4=2-2 + 4 = 2.

Answer: (−2,2)(-2, 2)

2

Reflections and rotations

A reflection flips a shape in a mirror line. Each point and its image are the same perpendicular distance from the line. Common lines: x=ax = a (vertical), y=by = b (horizontal), y=xy = x and y=−xy = -x (diagonal).

A rotation turns a shape about a fixed centre\textbf{centre} through an angle\textbf{angle} in a direction\textbf{direction} (clockwise or anticlockwise). Tracing paper helps: pin it at the centre and turn.

To find a centre of rotation, try points with tracing paper, or construct perpendicular bisectors of lines joining two points to their images — the centre is where they cross.

Example 1Triangle AA has vertices (1,1)(1, 1), (3,1)(3, 1) and (1,2)(1, 2). Find the vertices after reflection in y=xy = x.
1Reflecting in y=xy = x swaps the coordinates: (x,y)→(y,x)(x, y) \to (y, x).
Answer(1,1)(1, 1), (1,3)(1, 3) and (2,1)(2, 1)
Your turnSame method, new numbers — try it before moving on.

Rotate the point (2,5)(2, 5) through 90∘90^\circ clockwise about the origin.

Type coordinates like (2, -3).

Show worked solution
Solution
  1. 190∘90^\circ clockwise: (x,y)→(y,−x)(x, y) \to (y, -x).
  2. 2(5,−2)(5, -2).

Answer: (5,−2)(5, -2)

Tip — A rotation of 180∘180^{\circ} needs no direction, but 90∘90^{\circ} does. "Rotation 90∘90^{\circ} about (0,0)(0, 0)" without clockwise or anticlockwise loses a mark.

3

Enlargements

An enlargement multiplies distances from a centre\textbf{centre} by the scale factor\textbf{scale factor} kk. Draw rays from the centre through each vertex; the image vertex is kk times as far along.

A scale factor between 0 and 1 makes the shape smaller but is still called an enlargement.

A negative scale factor puts the image on the opposite side of the centre, upside down: with k=−2k = -2, each image point is twice as far from the centre in the opposite direction.

Example 1Enlarge the point P(4,3)P(4, 3) by scale factor −12-\tfrac12 with centre (2,1)(2, 1).
1Vector from centre to PP: (22)\begin{pmatrix} 2 \\ 2 \end{pmatrix}.
2Multiply by −12-\tfrac12: (−1−1)\begin{pmatrix} -1 \\ -1 \end{pmatrix}.
3Add to the centre.
AnswerP′=(1,0)P^{\prime} = (1, 0)
Your turnSame method, new numbers — try it before moving on.

Enlarge the point (5,3)(5, 3) by scale factor 2 with centre (1,1)(1, 1).

Type coordinates like (2, -3).

Show worked solution
Solution
  1. 1Vector from centre: (42)\begin{pmatrix} 4 \\ 2 \end{pmatrix}, doubled: (84)\begin{pmatrix} 8 \\ 4 \end{pmatrix}.
  2. 2Image: (1+8,1+4)=(9,5)(1 + 8, 1 + 4) = (9, 5).

Answer: (9,5)(9, 5)

Why this works

Working with the vector from the centre turns enlargement into arithmetic: multiply the vector by kk and add it to the centre. It works for any scale factor, including negatives.

4

Describing and combining transformations

Checklist for "describe fully": translation — vector; reflection — equation of mirror line; rotation — angle, direction, centre; enlargement — scale factor, centre.

A single transformation only: do not describe two transformations when one is asked for.

Combined transformations can often be replaced by one. Two reflections in parallel lines give a translation; two reflections in perpendicular lines through a point give a 180∘180^{\circ} rotation about that point.

Example 1Shape BB is the image of shape AA under a reflection in the xx-axis followed by a reflection in the yy-axis. Describe the single transformation that maps AA to BB.
1(x,y)→(x,−y)→(−x,−y)(x, y) \to (x, -y) \to (-x, -y).
2That is the effect of a half turn about the origin.
AnswerRotation of 180∘180^{\circ} about (0,0)(0, 0).

Think like an examiner

  • Use the full checklist of details for each transformation.
  • Use the word "enlargement" even for scale factors less than 1.
  • Describe one single transformation when asked.

Transformations

(x,y)→(y,x)(x, y) \to (y, x)
Reflection in y = x.
(x,y)→(−x,−y)(x, y) \to (-x, -y)
Rotation 180° about the origin.
P′=C+k(P−C)P^{\prime} = C + k(P - C)
Enlargement, centre C, factor k.

Watch out for these

Describing a rotation without its centre.
Give angle, direction and centre.
Writing a translation as coordinates (3,−2)(3, -2).
Use a column vector.
Calling a scale factor 12\tfrac12 a "reduction".
It is still an enlargement with scale factor 12\tfrac12.
Placing a negative enlargement on the same side of the centre.
Negative factors put the image on the opposite side.

Stretch yourself

Triangle TT has vertices (2,1)(2, 1), (4,1)(4, 1) and (2,4)(2, 4). It is rotated 90∘90^{\circ} anticlockwise about the origin, then reflected in the line y=xy = x. Find the image vertices and describe the single transformation equivalent to the combination.

Hint — A 90∘90^{\circ} anticlockwise rotation about the origin maps (x,y)→(−y,x)(x, y) \to (-y, x). Reflection in y=xy = x swaps coordinates.

Reveal solution
SolutionRotation: (2,1)→(−1,2)(2, 1) \to (-1, 2), (4,1)→(−1,4)(4, 1) \to (-1, 4), (2,4)→(−4,2)(2, 4) \to (-4, 2). Reflection in y=xy = x: (−1,2)→(2,−1)(-1, 2) \to (2, -1), (−1,4)→(4,−1)(-1, 4) \to (4, -1), (−4,2)→(2,−4)(-4, 2) \to (2, -4). Overall (x,y)→(−y,x)→(x,−y)(x, y) \to (-y, x) \to (x, -y), so every point keeps its xx-coordinate and its yy-coordinate changes sign: the single transformation is a reflection in the xx-axis (y=0y = 0). ■\blacksquare

Questions students ask

Which transformations give congruent shapes?
Translations, reflections and rotations. Enlargements give similar shapes (congruent only if the scale factor is 1 or −1).
How do I find the centre of an enlargement?
Draw lines through corresponding vertices of the object and image; they meet at the centre.
Is a rotation of 90° clockwise the same as 270° anticlockwise?
Yes, they have the same effect.

Key takeaways

  • Translation: column vector.
  • Reflection: equation of the mirror line.
  • Rotation: angle, direction and centre.
  • Enlargement: scale factor and centre; negatives put the image on the far side.
  • Combined transformations can often be replaced by a single one.

Exam-style questions

Practise it the way it is examined

3 original questions · 7 marks, written to match the style and mark allocation of the real papers. Work on paper, then open the mark scheme and tick the marks you earned — method marks count even if the final answer slips.

Question 1Grade 32 marks
  1. A triangle has vertices (1,2)(1, 2), (3,2)(3, 2) and (3,5)(3, 5). Write down the vertices of its reflection in the yy-axis.[2]
    Show mark scheme
Answer on paper first, then mark it.
Question 2Grade 53 marks
  1. Triangle AA has vertices (1,1)(1, 1), (3,1)(3, 1), (1,4)(1, 4). Triangle BB has vertices (2,2)(2, 2), (6,2)(6, 2), (2,8)(2, 8). Describe fully the single transformation that maps AA onto BB.[3]
    Show mark scheme
Answer on paper first, then mark it.
Question 3Grade 72 marks
  1. A shape is rotated 90∘90^\circ anticlockwise about the origin, then reflected in the line y=xy = x. Describe the single transformation that has the same effect.[2]
    Show mark scheme
Answer on paper first, then mark it.

Unlimited practice

Skill drill

A new question every time, marked instantly, with a full worked solution. Aim for a streak of five, then move up a level.

0 / 0 first-time correct Streak 0Best at this level: 0

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Test yourself

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