Heights: : 10; : 24; : 15; : 18.
- (a)Work out the frequency densities.[2]
- (b)Estimate the number of heights greater than 32.[2]
A histogram looks like a bar chart for continuous data, but with one crucial difference: when the classes have different widths, the height of each bar is not the frequency. It is the , chosen so that the of each bar represents the frequency. Getting that idea right is the whole of this topic.
The big picture
If a class twice as wide were drawn at its frequency, it would look twice as important simply because it is wide. Dividing frequency by class width fixes this: frequency density is frequency per unit, so the bar’s area — width × density — equals the frequency.
OCR histogram questions work in both directions: complete a table and draw the histogram, or read frequencies from a drawn histogram, often for part of a class, such as "estimate the number of values between 12 and 25".
Video by corbettmaths. The video’s own board label is retained; follow the specification reference and scope notes on this lesson for assessed content.
Viewing focus: Calculate frequency density for classes of unequal width
After watching, attempt these questions before opening the answers. You can also use the written lesson below.
After watching 1: A class of width 4 has frequency 20. What is its frequency density?
5. .
After watching 2: In a histogram, frequency is represented by:
The area of the bar. Area density × width.
What you'll learn
Frequency density .
Frequency frequency density × class width — the area of the bar.
Class width is the difference between the class boundaries: has width 5.
A class of width 15 has frequency 45. What is its frequency density?
Use a continuous horizontal scale with class boundaries; bars touch, with no gaps.
The vertical axis is labelled "frequency density" with an even scale.
Each bar spans its class exactly, with height equal to its frequency density.
Tip — Label the vertical axis "frequency density", not "frequency". Using frequency heights with unequal widths loses most of the marks.
To find the frequency of a class, multiply its height (frequency density) by its width.
If the vertical scale is not labelled with numbers, use a class whose frequency is known to work out what one unit of area represents.
The bar for has frequency density 0.8. What is the frequency?
Taking part of a class assumes values are spread evenly across it — the same assumption as reading from a cumulative frequency curve. That is why the answer is an estimate.
Find the total frequency and the median position .
Add class frequencies until you reach the class containing the median, then work out how far into that class you need to go.
The class has frequency 30. Estimate how many values lie between 10 and 18.
Think like an examiner
Histograms
Watch out for these
Stretch yourself
On a histogram with no numbers on the vertical axis, the bar for is 6 cm tall and represents 42 people. The bar for is 8 cm tall. How many people does it represent?
Hint — Work out how many people 1 cm² of bar represents, using horizontal distance in class units.
Questions students ask
Key takeaways
Exam-style questions
2 original questions · 7 marks, written to match the style and mark allocation of the real papers. Work on paper, then open the mark scheme and tick the marks you earned — method marks count even if the final answer slips.
Heights: : 10; : 24; : 15; : 18.
Use the same data (total 67).
Unlimited practice
A new question every time, marked instantly, with a full worked solution. Aim for a streak of five, then move up a level.
Generating a question…
Check the assessed scope and practical or mathematical requirements.
An external explanation or interactive activity to use alongside the lesson. It may include extension material.
Close the notes and answer from memory. Revisit any explanation you cannot yet reconstruct.
Test yourself
Answer a few questions, then review anything you missed.
Start with the quiz above to check the key ideas. You can also choose another topic from the practice library.