1PH0 · CP10.17(b)Core practical investigationsCore

CP10.17(b): Series and Parallel Lamp Circuits

Trace the circuit before connecting it. In a series arrangement there is one complete path, so the steady current is the same at different positions. The sum of the potential differences across components equals the supply potential difference in the simple model. Place a voltmeter across the two points of interest and an ammeter within the path whose current is needed.

35 min Video by Science School Core practical investigations
Edexcel Core Practical 9-1 GCSE P10.17 Electrical circuit to test series and parallel circuitsCurated by Kepler, not produced by us. Watch it before the notes below.
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Before you start

  • Use your teacher’s tier checklist: this overview can include Higher-only material, and is not a tier-specific revision list.
  • Pearson Edexcel separate GCSE Physics 1PH0. Use the original core-practical reference and retain every specified subpart; two guides can develop different parts of one core reference.
  • Identify a junction, a branch and the two terminals of an electrical component.
  • Use the centre’s approved supervised method and equipment limits. These notes prepare you to explain and evaluate practical work; they do not replace carrying it out and recording the evidence.

Watch, pause, try

Video by Science School. This demonstration develops the series/parallel comparison for CP10.17. Use measured lamp and supply readings and retain the separate resistor/lamp characteristics investigation.

Viewing focus: Construct and check series and parallel arrangements from diagrams

After watching, attempt these questions before opening the answers. You can also use the written lesson below.

After watching 1: What two measured relationships would you test in a parallel circuit?

Show answer and reasoning

Compare voltage across branches sharing junctions, and compare supply current with the sum of branch currents under stable conditions.

After watching 2: Why is a fixed-resistance calculation potentially misleading when the same lamp is moved between series and parallel arrangements?

Show answer and reasoning

Its voltage, current and filament temperature can change. Use operating V and I to compare resistance and power rather than carrying one assumed value into both circuits.

What you'll be able to do

  • Construct and check series and parallel arrangements from diagrams
  • Compare supply and branch measurements
  • Use measured lamp operating conditions rather than fixed-resistance assumptions
1

Predict what each instrument will measure

Trace the circuit before connecting it. In a series arrangement there is one complete path, so the steady current is the same at different positions. The sum of the potential differences across components equals the supply potential difference in the simple model. Place a voltmeter across the two points of interest and an ammeter within the path whose current is needed.

In a parallel arrangement, branches share the same pair of junctions and therefore have the same potential difference. Current divides at a junction and the branch currents sum to the supply current. Lines crossing on a diagram do not necessarily form a junction: use the connection marks. Check for a complete route and for unintended wires that bypass a component.

2

Compare evidence from resistors and lamps

Measure supply voltage and relevant currents in a series circuit, then in a parallel circuit using the specified components. Keep a record of the actual arrangement, meter positions and supply setting. A real supply can change its terminal voltage under a different load, so “same knob position” does not guarantee exactly the same measured voltage.

For identical filament lamps on an appropriate fixed-voltage supply, parallel branches can each receive the full terminal potential difference, while series lamps share it. Brightness depends on the power at each lamp’s operating condition. Because filament resistance changes with temperature, use measured V and I and P = VI rather than assuming an unchanged lamp resistance in every connection.

CP10.17(b) requires parallel filament-lamp circuits with ammeters and voltmeters, compared with the initial series arrangement. Record potential difference and current, include V = IR analysis and do not replace the lamp comparison with only ideal fixed resistors.

3

Explain a disagreement before changing the theory

Small differences between a measured supply current and summed branch currents can reflect instrument resolution, timing or changed conditions if the circuit was rewired between readings. Use appropriate simultaneous measurements or repeat under stable conditions. Do not claim charge is consumed to explain a series-current difference; check the connections and measurement process.

Adding a parallel branch increases total current for an ideal fixed-voltage source with positive-resistance loads. A supply’s current limit or internal resistance can alter the observed voltage and brightness. Record these limitations and distinguish the ideal prediction from the actual source. Switch off before rewiring and follow component ratings and current limits.

4

Worked applications

Attempt these problems on paper before opening the worked reasoning. Explain your steps as well as giving a final answer.

Example 1Two series components have potential differences 2.4 V and 3.6 V. The steady current is 0.20 A. Find supply voltage and component powers.
1Supply V = 2.4 + 3.6 = 6.0 V.
2First P = 2.4 × 0.20 = 0.48 W.
3Second P = 3.6 × 0.20 = 0.72 W.
Answer
6.0 V supply; powers 0.48 W and 0.72 W.
Example 2A parallel circuit has branch currents 0.18 A and 0.27 A at a measured 6.0 V. Find supply current and total power.
1Supply I = 0.18 + 0.27 = 0.45 A.
2Total P = VI = 6.0 × 0.45.
Answer
0.45 A and 2.7 W in the stated steady model.
Example 3A lamp is measured at 3.0 V, 0.20 A in one arrangement and 6.0 V, 0.30 A in another. Compare power and explain why the same resistance should not be assumed.
1P values are 3.0 × 0.20 = 0.60 W and 6.0 × 0.30 = 1.80 W.
2V/I values are 15 Ω and 20 Ω.
3The filament’s operating temperature changes its resistance.
Answer
Power triples in these measurements; the lamp does not have one fixed resistance across them.

Common mistakes to avoid

Treating a crossing as a connection without checking the diagram.
Identify the junction symbols and trace complete paths.
Assuming the supply terminal voltage is unchanged under any load.
Measure the relevant voltage and recognise source limits.

Key takeaways

  • You can construct and check series and parallel arrangements from diagrams.
  • You can compare supply and branch measurements.
  • You can use measured lamp operating conditions rather than fixed-resistance assumptions.

Apply it in an exam

Question 1: A lamp is measured at 3.0 V, 0.20 A in one arrangement and 6.0 V, 0.30 A in another. Compare power and explain why the same resistance should not be assumed.

Show answer and reasoning

Power triples in these measurements; the lamp does not have one fixed resistance across them.

  • P values are 3.0 × 0.20 = 0.60 W and 6.0 × 0.30 = 1.80 W.
  • V/I values are 15 Ω and 20 Ω.
  • The filament’s operating temperature changes its resistance.

Explore further

Return to this tomorrow

Close the notes and answer from memory. Revisit any explanation you cannot yet reconstruct.

  • What happens to steady current through successive series components?
  • Why use measured V and I when comparing lamp brightness?

Test yourself

Answer a few questions, then review anything you missed.

Next step

Keep practising

Start with the quiz above to check the key ideas. You can also choose another topic from the practice library.

Browse practice topics

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